The horizontal component of tensile force in a wire that makes 60° with horizontal and is carrying a force of 20 kN is

Correct option is A

The horizontal component of the tensile force can be calculated using the formula:
Horizontal component = F × cos(θ)
Where:
F = 20 kN (tensile force)
Θ = 60° (angle with the horizontal)
Horizontal Component = 20 kN × cos (60°) = 20kN × 0.5 = 10kN
So, the horizontal component of the tensile force is 10 kN.