The given graph shows the percentage-wise distribution of different mobile phone models (A to F) produced by a mobile company in 2008 and 2009. The total number of mobile phones produced in 2008 was 4,50,000 and that in 2009 was 6,40,000.

(If a value for any model in between a range, consider it to be at midpoint, e.g any point between 10 and 20 should be considered 15.)

What is the difference between the numbers of Model B sets produced in 2008 and 2009?

Correct option is B

Given:

The total number of mobile phones produced in 2008 = 4,50,000

The total number of mobile phones produced in 2009 = 6,40,000

Solution:

Percentage of Model B sets produced in 2008 = 15%

Number of Model B in 2008= $$15\% \times 4,50,000 = \frac{15}{100} \times 4,50,000 = 67,500$$​​

Percentage of Model B sets produced in 2009 = 20%

Number of Model B in 2009 =$$20\% \times 6,40,000 = \frac{20}{100} \times 6,40,000 = 1,28,000$$​

Difference between the number of Model B sets produced in 2008 and 2009 = 1,28,000 - 67,500 = 60,500