Correct option is B
Solution: f(x)=2x+∣x−1∣Case 1: x>1=>f(x)=2x+(x−1)=3x−1Case 2: x<1=>f(x)=2x−(x−1)=x+1Left-hand derivative at x=1:f′(x)=1Right-hand derivative at x=1:f′(x)=3Since fL′(1)=fR′(1), function is not differentiable at x=1However, f(x) is continuous at x=1Correct answer: (B) Continuous