The following table shows the marks obtained by two students A and B in different subjects.

Subject	A	Maximum marks	B	Maximum marks
Mathematics	42	50	35	50
Physics	45	50	33	50
Chemistry	40	50	40	50
Biology	33	50	42	50

What is the difference between the aggregate percentage marks of A and B?

Correct option is D

Formula Used:

$$\text{Percentage} = \frac{\text{Part}}{\text{Whole}} \times 100$$​

Solution:

Aggregate Percentage for Student A:

Total marks obtained by A = 42 + 45 + 40 + 33 = 160

Total maximum marks for A = 50 + 50 + 50 + 50 = 200

Aggregate percentage of A = $$\frac{160}{200} \times100$$ = 80%

2. Percentage for Student B:

Total marks obtained by B = 35 + 33 + 40 + 42 = 150

Total maximum marks for B = 50 + 50 + 50 + 50 = 200

Aggregate percentage of B = $$\frac{150}{200} \times100$$​ = 75%

the difference in aggregate percentages:

Difference = Aggregate percentage of A - Aggregate percentage of B

Difference = 80% - 75% = 5%

Therefore, the difference between the aggregate percentage marks of A and B is 5%.

Thus, correct answer is option (D).