The following question is based on the given seven, 3-digit numbers. 
(Left) 347, 486, 627, 113, 721, 418, 779 (Right) 
(For example, 456: 6 = digit in unit's place, 5 = digit in ten's place, 4 = digit in hundred's place) 
NOTE - All operations to be done from left to right. 
If 2 is added to the digit in hundred's place of each number given above, in how many numbers will be the modified digit in hundred's place be exactly divisible by the digit appearing in the ten's place?​

Given: (Left) 347, 486, 627, 113, 721, 418, 779 (Right) 

Add 2 to the hundred's digit of each number. Check if the modified hundred's digit is divisible by the ten's digit.

1. 347

Hundreds = 3 → 3 + 2 = 5, Tens = 4 (5 not divisible by 4)

2. 486

Hundreds = 4 → 4 + 2 = 6, Tens = 8 (6 not divisible by 8)

3. 627

Hundreds = 6 → 6 + 2 = 8, Tens = 2 (8 divisible 2)

4. 113

Hundreds = 1 → 1 + 2 = 3, Tens = 1 (3 divisible 1)

5. 721

Hundreds = 7 → 7 + 2 = 9, Tens = 2 (9 not divisible by 2)

6. 418

Hundreds = 4 → 4 + 2 = 6, Tens = 1 (6 divisible 1)

7. 779

Hundreds = 7 → 7 + 2 = 9, Tens = 7 (9 not divisible by 7)

3 numbers will be the modified digit in hundred's place be exactly divisible by the digit appearing in the ten's place.

Thus, correct option is (d).