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    The equation of motion of a spring-mass-damper system is given by ​x¨+4x˙+16x=12sin5t\ddot{x} +4\dot{x} + 16x = 12sin 5tx¨+4x˙+16x=12sin5t​​What is t
    Question

    The equation of motion of a spring-mass-damper system is given by
    x¨+4x˙+16x=12sin5t\ddot{x} +4\dot{x} + 16x = 12sin 5t​​
    What is the damping factor of the system?

    A.

    1

    B.

    0.5

    C.

    0.25

    D.

    0.75

    Correct option is B

    We are given a standard second-order linear differential equation for a spring-mass-damper system:x¨+2ζωnx˙+ωn2x=F(t)mCompare this with the given equation:x¨+4x˙+16x=12sin5tFrom comparison:2ζωn=4ωn2=16=>ωn=16=4Now plug into the damping ratio formula:ζ=2ζωn2ωn=424=48=0.5\begin{aligned}&\text{We are given a standard second-order linear differential equation for a \textbf{spring-mass-damper system}:} \\&\ddot{x} + 2\zeta \omega_n \dot{x} + \omega_n^2 x = \frac{F(t)}{m} \\[1em]&\text{Compare this with the given equation:} \\&\ddot{x} + 4\dot{x} + 16x = 12\sin 5t \\[1em]&\text{From comparison:} \\&\bullet \quad 2\zeta \omega_n = 4 \\&\bullet \quad \omega_n^2 = 16 \Rightarrow \omega_n = \sqrt{16} = 4 \\[1em]&\text{Now plug into the damping ratio formula:} \\&\zeta = \frac{2\zeta \omega_n}{2 \omega_n} = \frac{4}{2 \cdot 4} = \frac{4}{8} = \boxed{0.5}\end{aligned}​​

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