The emf induced in the armature of a shunt generator is 600V. The armature resistance is 0.1 ohm. If the armature current is 200A, the terminal voltage will be:

Correct option is D

​$$Eg = 600 \text{ V}, Ra = 0.1 \Omega, Ia = 200 \text{ A}$$

$$V_t = E_g - I_a R_a$$

$$V_t = 600 - 200(0.1) = 580 \text{ V}$$​​​​