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    The correct relation between the focal length of a lens and its power is:
    Question

    The correct relation between the focal length of a lens and its power is:

    A.

    P=1fP = \frac{1}{f}​​

    B.

    P=1/fP = -1/f​​

    C.

    PfP \propto f​​

    D.

    P=fP = f​​

    Correct option is A

    The correct answer is:(A) P = 1/f

    The power of a lens (P) is related to the focal length (f) by the formula:P=1fP = \frac{1}{f}​​

    Where:

    • P is the power of the lens in diopters (D),
    • f is the focal length of the lens in meters (m).

    This formula is correct and applies universally to both convex (converging) and concave (diverging) lenses.

    The power of a lens is the inverse of its focal length. The sign of the power will depend on whether the lens is converging or diverging:

    • For convex lenses, the focal length is positive, and the power is positive.
    • For concave lenses, the focal length is negative, and the power is negative.

    Information booster:

     P = −1/f: This formula is not universally correct. The formula for the power of a lens is P=1/f P=1fP = \frac{1}{f}
    , and the negative sign applies only to concave (diverging) lenses, not as a general rule.

    P ∝ f: This is incorrect. The power is inversely proportional to the focal length, not directly proportional. As the focal length increases, the power decreases.

     P = f: This is incorrect because it does not represent the correct relationship between power and focal length.

    Key Points:

    • P=1f P = \frac{1}{f}​The power of a lens is given by
    • The sign of the power depends on the type of lens: positive for converging lenses and negative for diverging lenses.

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