The circumference of the base of a solid right circular cylinder is 136.4 cm and its height is 50  cm. What is the volume (in $$cm^3$$) of the cylinder? (Take π = 22/7 ).

Correct option is A

Given:
Circumference of the base of the cylinder = 136.4 cm
Height of the cylinder = 50 cm
​$$\pi = \frac{22}{7}$$​
Formula Used:
The volume of a cylinder is given by:
​$$V= \pi r^2 h$$​
Where:
r is the radius of the base.
h is the height of the cylinder.
The circumference of the base is given by:
Circumference = 2πr

​$$r = \frac{\text{Circumference}}{2\pi}$$​
Solution: ​

Applying the formula for radius;

​$$r = \frac{\text{Circumference}}{2\pi}$$​

​$$r= \frac{136.4 \times 7}{44}$$​

r =$$\frac{954.8}{44} = 21.7 \text{ cm}$$ 

Now, Volume of the cylinder;

V = $$\frac{22}{7} \times (21.7)^2 \times 50$$​

=$$\frac{22}{7} \times 470.89 \times 50$$​

=$$\frac{22 \times 470.89 \times 50}{7}$$​

= 73997 cm³​

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