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The boolean expression Z=A‾ B‾C‾D+A‾BCD‾+AB‾C‾D+ABC‾D‾Z = \overline{A}\, \overline{B} \overline{C} D + \overline{A} B C \overline{D} + A \overlin
Question

The boolean expression Z=A BCD+ABCD+ABCD+ABCDZ = \overline{A}\, \overline{B} \overline{C} D + \overline{A} B C \overline{D} + A \overline{B} \overline{C} D + A B \overline{C} \overline{D}​ can be minimized to?

A.

Z=ABC+B CD+ABCDZ = \overline{A}BC + \overline{B}\,\overline{C}D + AB\overline{C}\overline{D}

B.

Z=ABCD+B CD+ABCDZ = \overline{A}BC\overline{D} + \overline{B}\,\overline{C}D + AB\overline{C}\overline{D}

C.

Z=ABCD+BD+BCDZ = \overline{A}BC\overline{D} + \overline{B}D + B\overline{C}\overline{D}

D.

Z=ABCD+B CD+ABZ = \overline{A}BC\overline{D} + \overline{B}\,\overline{C}D + AB

Correct option is B

All terms share a common literal D\overline{D}​, which is factored out. The remaining expression simplifies using Boolean identities, leading to:

Z=ABD+BCD+ABCDZ = \overline{A} B \overline{D} + \overline{B} C D + A B C \overline{D}​​

Important Key Points:

  1. Common literal factoring (e.g. D\overline{D}​,) is the first simplification step.
  2. Use Boolean identities likeX+X=1 and X+0=X X + X' = 1 \text{ and } X + 0 = X​ for simplification.
  3. Grouping terms by common variables helps in compacting expressions.

Knowledge Booster:

  • Option A: Contains termABC\overline{A} B C​, which is not present in the original expression.
  • Option C: Includes incorrect simplification likeBD \overline{B D}​, which doesn’t logically follow from grouping.
  • Option D: Contains AB, which is overly generalized and cannot be derived from any valid group in the original.

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