Correct option is C
Given:
Average Speed of Gaurav during a two-ways journey = 15km/hr
Speed while going = 20km/hr
Formula Used:
Time=SpeedDistance
Solution:
Let the distance on one side be x
Then time taken while going =20x
Total time taken of the journey =152x
Let the speed while returning be v
Then:
152x=20x+vx
vx=608x−3x
vx=605x
v=5x60×x=12km/hr