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The average speed of Gaurav during a two-way journey is 15 km/h. If he walked a distance of 20 km every hour while going, then his speed while returni
Question

The average speed of Gaurav during a two-way journey is 15 km/h. If he walked a distance of 20 km every hour while going, then his speed while returning will be:

A.

11 km/h

B.

15 km/h

C.

12 km/h

D.

10 km/h

Correct option is C

Given:
Average speed for the entire journey = 15 km/h
Distance while going = Distance while returning = 20 km
Speed while going = 20 km/h
Concept Used:
The formula for average speed over a round trip is:
Average Speed=2×Speed1×Speed2Speed1+Speed2\text{Average Speed} = \frac{2 \times \text{Speed}_1 \times \text{Speed}_2}{\text{Speed}_1 + \text{Speed}_2}​​
where Speed1\text{Speed}_1​ is the speed while going, and Speed2\text{Speed}_2​​ is the speed while returning.
Solution:
Substituting the given values into the average speed formula:
15=2×20×Speed220+Speed215 = \frac{2 \times 20 \times \text{Speed}_2}{20 + \text{Speed}_2}​​
15(20+Speed2)=2×20×Speed215(20 + \text{Speed}_2) = 2 \times 20 \times \text{Speed}_2​​
300+15×Speed2=40×Speed2300 + 15 \times \text{Speed}_2 = 40 \times \text{Speed}_2​​
300=40×Speed215×Speed2300 = 40 \times \text{Speed}_2 - 15 \times \text{Speed}_2​​
300=25×Speed2300 = 25 \times \text{Speed}_2​​
Speed2=30025=12\text{Speed}_2 = \frac{300}{25} = 12​​
Thus, The speed while returning is 12 km/h.

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