The area of the region enclosed between $$y^2 = 4x \quad \text{and} \quad x = 1 \quad \text{and} \quad x = 3.$$ in the first quadrant is:

Correct option is A

Given curve is 

​$$y^2 = 4x \quad \text{and} \quad x = 1, x = 3\\\text{Area of the bounded region} = \int_1^3 y \, dx\\= \int_1^3 2\sqrt{x} \, dx = 2 \times \frac{2}{3} \left[ x^{3/2} \right]_1^3 \\= \frac{4}{3} \left( 3\sqrt{3} - 1 \right)$$​​