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Taking 1.33 as an approximation to 43\frac{4}{3}34​, the percentage error is​
Question

Taking 1.33 as an approximation to 43\frac{4}{3}, the percentage error is​

A.

0.25

B.

0.37

C.

0.75

D.

0.05

Correct option is A

Solution:

True Value=43=1.3,Approximate Value=1.33Percentage Error=True ValueApproximate ValueTrue Value×100=1.33331.331.3333×100=0.00331.3333×1000.00331.3333×1000.002475×100=0.2475%0.25%\text{True Value} = \frac{4}{3} = 1.\overline{3}, \quad \text{Approximate Value} = 1.33 \\[8pt]\text{Percentage Error} = \left| \frac{\text{True Value} - \text{Approximate Value}}{\text{True Value}} \right| \times 100 \\[8pt]= \left| \frac{1.3333\ldots - 1.33}{1.3333\ldots} \right| \times 100 \\[8pt]= \left| \frac{0.0033\ldots}{1.3333\ldots} \right| \times 100 \approx \frac{0.0033}{1.3333} \times 100 \\[8pt]\approx 0.002475 \times 100 = 0.2475\% \approx \boxed{0.25\%}


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