Correct option is ASolution:True Value=43=1.3‾,Approximate Value=1.33Percentage Error=∣True Value−Approximate ValueTrue Value∣×100=∣1.3333…−1.331.3333…∣×100=∣0.0033…1.3333…∣×100≈0.00331.3333×100≈0.002475×100=0.2475%≈0.25%\text{True Value} = \frac{4}{3} = 1.\overline{3}, \quad \text{Approximate Value} = 1.33 \\[8pt]\text{Percentage Error} = \left| \frac{\text{True Value} - \text{Approximate Value}}{\text{True Value}} \right| \times 100 \\[8pt]= \left| \frac{1.3333\ldots - 1.33}{1.3333\ldots} \right| \times 100 \\[8pt]= \left| \frac{0.0033\ldots}{1.3333\ldots} \right| \times 100 \approx \frac{0.0033}{1.3333} \times 100 \\[8pt]\approx 0.002475 \times 100 = 0.2475\% \approx \boxed{0.25\%}True Value=34=1.3,Approximate Value=1.33Percentage Error=True ValueTrue Value−Approximate Value×100=1.3333…1.3333…−1.33×100=1.3333…0.0033…×100≈1.33330.0033×100≈0.002475×100=0.2475%≈0.25%