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Suppose f:[0,1]×[0,1]→(0,1)×(0,1)f:[0,1]\times[0,1] \to (0,1)\times (0,1) f:[0,1]×[0,1]→(0,1)×(0,1) is a continuous,non constant function. W
Question

Suppose f:[0,1]×[0,1](0,1)×(0,1)f:[0,1]\times[0,1] \to (0,1)\times (0,1)  is a continuous,

non constant function. Which of the following statements 

are NOT true ?

A.

image of f is uncountable.

B.

image of f is path connected set .

C.

image of f is a compact set.

D.

image of f has non-empty interior.

Correct option is D

Option A and C:\textbf{Option A and C:}​​

f is given continuous \implies ​f maps compact set to compact set. 

statement C true.\implies \textbf{statement C true.}​​

Furthermore, range is given (0,1) ×\times​ (0,1) So , 

the image of fff must be uncountable, as a compact subset of a metric space like

(0,1)×(0,1)(0,1) \times (0,1)(0,1)×(0,1) that is nontrivial must be uncountable.​

statement A is true. \textbf{statement A is true. }​​

Option B\textbf{Option B}​​

The function fff is continuous, and the domain [0,1]×[0,1][0,1] \times [0,1][0,1]×[0,1] is path-connected.

The continuous image of a path-connected set is also path-connected.

Therefore, the image of fff is path-connected.​

Hence, statement given in option B is also true\textbf{Hence, statement given in option B is also true}

as all statements given in Option A,B and C are true. Option D must be correct.

Also , From given conditions f need not have empty interior.

So, statement given in option D is false \textbf{So, statement given in option D is false }​​

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