Suppose an electric refrigerator of 500 W operates 12 hour/day. What is the cost of the energy to operate it for 30 days at ₹5.00 per kW h?​

Correct option is B

​The correct answer is (b) ₹900/-

Explanation: 

To calculate the cost of operating the refrigerator, let's follow these steps:

Given:

• Power consumption of the refrigerator = 500 W = 0.5 kW (since 1 kW = 1000 W)
• Operating time per day = 12 hours
• Duration of operation = 30 days
• Cost of electricity = ₹5.00 per kWh

Step 1: Calculate the energy consumption per day

Energy consumed per day = Power × Time

$$\text{Energy per day}=0.5\text{kW}\times 12\text{hours}=6\text{kWh}$$

Step 2: Calculate the total energy consumption for 30 days

$$\text{Total energy for 30 days}=6\text{kWh/day}\times 30\text{days}=180\text{kWh}$$

Step 3: Calculate the total cost

$$\text{Total cost}=\text{Total energy}\times \text{Cost per kWh}$$Total cost=180kWh×5₹/kWh=900₹\text{Total cost} = 180 \, \text{kWh} \times 5 \, \text{₹/kWh} = 900 \, \text{₹}Total cost=180kWh×₹5/kWh=₹900

​​