Starting from rest a vehicle accelerates at the rate of 2 m/s2 towards east for 10s. It then stops suddenly. It then accelerates again at a rate of 4√2 m/s2 for next 10 s towards south and then again comes to rest. The net displace- ment of the vehicle from the starting point is

Correct option is C

The correct answer is (c) 300 m. Step-by-Step Explanation: 1. Eastward Motion: · The vehicle accelerates at 2 m/s² for 10 seconds. · Displacement = (1/2) × Acceleration × Time² · Displacement = 100 meters east. 2. Southward Motion: · The vehicle accelerates at 4√2 m/s² for 10 seconds. · Displacement = (1/2) × Acceleration × Time² · Displacement = approximately 282.84 meters south. 3. Net Displacement: · Use the Pythagorean theorem to calculate the net displacement. · Net displacement = √(Eastward displacement² + Southward displacement²) · Net displacement = approximately 300 meters. Final Answer: The net displacement of the vehicle from the starting point is 300 meters, so the correct option is (c) 300 m.