​Solve the following.

80 ÷ (16 ÷ 2) + {[(6 × 5) – 15 × 2 + 4] – 12}

Correct option is C

Given:

80 ÷ (16 ÷ 2) + {[(6 × 5) – 15 × 2 + 4] – 12}

Concept Used:

$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline\text{Brackets} &[],{}, () \\ \hline \text{Orders, of} & ^x(power), √ (root) , of \\ \hline \text{Division}& ÷ \\\hline \text{Multiplication} & × \\ \hline \text{Addition} & + \\ \hline \text{Subtraction} & - \\\hline\end{array}$$

Solution:

80 ÷ (16 ÷ 2) + {[(6 × 5) – 15 × 2 + 4] – 12}

= 80 ÷ (16 ÷ 2) + {[(30) – 15 × 2 + 4] – 12}

=80 ÷ (16 ÷ 2) + {[30 – 30 + 4] – 12}

=80 ÷ (16 ÷ 2) + {4 – 12}

=80 ÷ 8 -8

=10 - 8 =2

Option (c) is right