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Solve the following.55+[29−{25−(6−24÷6×8)}]=55+[29-\{25-(6-24÷6×8)\}]=55+[29−{25−(6−24÷6×8)}]=​ ?
Question

Solve the following.

55+[29{25(624÷6×8)}]=55+[29-\{25-(6-24÷6×8)\}]=​ ?

A.

33

B.

41

C.

63

D.

59

Correct option is A

Given:

55+[29{25(624÷6×8)}]55+[29-\{25-(6-24÷6×8)\}]

Concept Used:

Operation preference wiseSymbolBrackets[],,()Orders, ofx(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline\text{Brackets} &[],{}, () \\ \hline \text{Orders, of} & ^x(power), √ (root) , of \\ \hline \text{Division}& ÷ \\\hline \text{Multiplication} & × \\ \hline \text{Addition} & + \\ \hline \text{Subtraction} & - \\\hline\end{array}​​

Solution:

55+[29{25(624÷6×8)}]55+[29-\{25-(6-24÷6×8)\}]

=55+[29{25(64×8)}]55+[29-\{25-(6-4×8)\}]

=55+[29{25(632)}]55+[29-\{25-(6-32)\}]

=55+[29{25+26}]55+[29-\{25+26\}]

=55+[2951]55+[29-51]

= 55 - 22

= 33

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