Solve the following:

​$$(243)^2÷(27)^2×16÷8=?$$​​

Correct option is A

Given:

​$$(243)^2÷(27)^2×16÷8$$

Concept Used:

​$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline\text{Brackets} &[],{}, () \\ \hline \text{Orders, of} & ^x(power), √ (root) , of \\ \hline \text{Division}& ÷ \\\hline \text{Multiplication} & × \\ \hline \text{Addition} & + \\ \hline \text{Subtraction} & - \\\hline\end{array}$$

Solution:

​$$(243)^2÷(27)^2×16÷8$$

=$$\left( \frac{243}{27} \right)^2 \times 2$$

= 9² ​$$\times 2$$

=$$81 \times 2 =162$$​​