Six pipes are required to fill a tank in 1 hour 45 minutes. How long will it take if only three pipes of the same type are used?

Correct option is D

Given:

Time taken by 6 pipe to fill a tank = 1 hour 45 minutes =$$\frac{7}{4}$$​ hours

To find: time taken by 3 pipes

Formula Used:

Capacity = filling rate × number of pipes × time

Solution:

Capacity of tank is equal in both scenario;

So,

6 × $$\frac{7}{4}$$​ = 3 × time

time = 2 ×$$\frac{7}{4}$$​ = $$\frac{7}2$$​hours = 3 hours 30 min