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    Six pipes are required to fill a tank in 1 hour 45 minutes. How long will it take if only three pipes of the same type are used?
    Question

    Six pipes are required to fill a tank in 1 hour 45 minutes. How long will it take if only three pipes of the same type are used?

    A.

    3 h 20 min

    B.

    3 h 15 min

    C.

    3 h 40 min

    D.

    3 h 30 min

    Correct option is D

    Given:

    Time taken by 6 pipe to fill a tank = 1 hour 45 minutes =74 \frac{7}{4}​ hours

    To find: time taken by 3 pipes

    Formula Used:

    Capacity = filling rate × number of pipes × time

    Solution:

    Capacity of tank is equal in both scenario;

    So,

    6 × 74\frac{7}{4}​ = 3 × time

    time = 2 ×74 \frac{7}{4}​ = 72\frac{7}2 ​hours = 3 hours 30 min

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