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Six pipes are required to fill a tank in 1 hour 45 minutes. How long will it take if only three pipes of the same type are used?
Question

Six pipes are required to fill a tank in 1 hour 45 minutes. How long will it take if only three pipes of the same type are used?

A.

3 h 20 min

B.

3 h 15 min

C.

3 h 40 min

D.

3 h 30 min

Correct option is D

Given:

Time taken by 6 pipe to fill a tank = 1 hour 45 minutes =74 \frac{7}{4}​ hours

To find: time taken by 3 pipes

Formula Used:

Capacity = filling rate × number of pipes × time

Solution:

Capacity of tank is equal in both scenario;

So,

6 × 74\frac{7}{4}​ = 3 × time

time = 2 ×74 \frac{7}{4}​ = 72\frac{7}2 ​hours = 3 hours 30 min

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