Correct option is D
Given:
(1) E is riding slower than F. → E < F
(2)A is riding faster than C but slower than D. → C < A < D
(3) D is riding slower than B but faster than F. → F < D < B
(4) C is riding faster than F. → F < C
(2)A is riding faster than C but slower than D. → C < A < D
(3) D is riding slower than B but faster than F. → F < D < B
(4) C is riding faster than F. → F < C
Arrange the order from slowest to fastest:
From condition (1):
E < F
From condition (4):
E < F < C
From condition (2):
E < F < C < A < D
From condition (3):
E < F < C < A < D < B
Thus, B is the fastest.
Therefore, the correct option is (d) B
From condition (1):
E < F
From condition (4):
E < F < C
From condition (2):
E < F < C < A < D
From condition (3):
E < F < C < A < D < B
Thus, B is the fastest.
Therefore, the correct option is (d) B