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    ​sin⁡−1(45)−sin⁡−1(513)= ?\sin^{-1}\left(\frac{4}{5}\right) - \sin^{-1}\left(\frac{5}{13}\right) = \, ?sin−1(54​)−sin−1(135​)=?​​
    Question

    sin1(45)sin1(513)= ?\sin^{-1}\left(\frac{4}{5}\right) - \sin^{-1}\left(\frac{5}{13}\right) = \, ?​​

    A.

    sin1(3363)\sin^{-1}\left(\frac{33}{63}\right)​​

    B.

    sin1(3365)\sin^{-1}\left(\frac{33}{65}\right)​​

    C.

    sin1(5365)\sin^{-1}\left(\frac{53}{65}\right)​​

    D.

    sin1(6533)\sin^{-1}\left(\frac{65}{33}\right)​​

    Correct option is B

    We can use the subtraction formula for inverse sine:sin1Asin1B=sin1((A1B2B1A2))Identify A and BA=45,B=513Compute 1A2 and 1B21A2=1(45)2=11625=925=351B2=1(513)2=125169=144169=1213Apply the subtraction formulasin1(45)sin1(513)=sin1(45121351335)=sin1(48651565)=sin1(3365)\text{We can use the subtraction formula for inverse sine:} \\\sin^{-1} A - \sin^{-1} B = \sin^{-1} \left( \left( A \sqrt{1 - B^2} - B \sqrt{1 - A^2} \right) \right) \\\textbf{Identify A and B} \\A = \frac{4}{5}, \quad B = \frac{5}{13} \\\textbf{Compute } \sqrt{1 - A^2} \text{ and } \sqrt{1 - B^2} \\\sqrt{1 - A^2} = \sqrt{1 - \left( \frac{4}{5} \right)^2} = \sqrt{1 - \frac{16}{25}} = \sqrt{\frac{9}{25}} = \frac{3}{5} \\\sqrt{1 - B^2} = \sqrt{1 - \left( \frac{5}{13} \right)^2} = \sqrt{1 - \frac{25}{169}} = \sqrt{\frac{144}{169}} = \frac{12}{13} \\\textbf{Apply the subtraction formula} \\\sin^{-1} \left( \frac{4}{5} \right) - \sin^{-1} \left( \frac{5}{13} \right) = \sin^{-1} \left( \frac{4}{5} \cdot \frac{12}{13} - \frac{5}{13} \cdot \frac{3}{5} \right) \\= \sin^{-1} \left( \frac{48}{65} - \frac{15}{65} \right) = \sin^{-1} \left( \frac{33}{65} \right)​​

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