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Simplify:​Z=AB+ABCˉZ = AB + AB\bar{C}Z=AB+ABCˉ​​
Question

Simplify:
Z=AB+ABCˉZ = AB + AB\bar{C}​​

A.

A + B

B.

AB

C.

ABCˉAB\bar{C}​​

D.

A+BCˉA + B\bar{C}​​

Correct option is B

Z=AB+ABCˉ=AB(1+Cˉ)Z = AB + AB\bar{C}= AB(1 + \bar{C})​ by factoring AB.
Using the Boolean identity 1 + X = 1, we get 1+Cˉ=11 + \bar C = 1​.
Hence Z=AB1=ABZ = AB \cdot 1 = AB​.
Intuitively, once AB = 1, the extra term ABCˉAB\bar C​ doesn’t add any new minterms—it’s redundant.
Therefore, the simplified expression is AB, independent of C.
Important Key Points

  1. Distributive law: XY + XY' = X(Y + Y').
  2. Complementarity: Y + Y' = 1.
  3. Identity: X1=XX \cdot 1 = X​.
  4. Redundancy check: If one term fully contains another, the larger one is redundant.
  5. Result: AB+ABCˉ=>ABAB + AB\bar C \Rightarrow AB​.

Knowledge Booster

  • A common quick rule: X + XY = X. Here, let X = AB and Y=CˉY=\bar C​; then AB+ABCˉ=ABAB + AB\bar C = AB​.
  • Karnaugh-map view: All cells where AB = 1 are already covered; restricting C = 0 doesn’t add coverage.

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