Correct option is B
Given triad:
339 – 663 – 555
348 – 636 – 555
Logic: sum of the digits in all three numbers is 15.
339:
3 + 3 + 9 = 15
3 + 3 + 9 = 15
663:
6 + 6 + 3 = 15
6 + 6 + 3 = 15
555:
5 + 5 + 5 = 15
5 + 5 + 5 = 15
Option A: 164 – 542 – 614
164:
1 + 6 + 4 = 11
1 + 6 + 4 = 11
542:
5 + 4 + 2 = 11
5 + 4 + 2 = 11
614:
6 + 1 + 4 = 11
6 + 1 + 4 = 11
The sum of the digits is 11, not 15. So, Option A is incorrect.
Option B: 195 – 285 – 348
195:
1 + 9 + 5 = 15
1 + 9 + 5 = 15
285:
2 + 8 + 5 = 15
2 + 8 + 5 = 15
348:
3 + 4 + 8 = 15
3 + 4 + 8 = 15
The sum of the digits is 15 for all three numbers, so Option B is correct.
Option C: 161 – 512 – 710
161:
1 + 6 + 1 = 8
1 + 6 + 1 = 8
512:
5 + 1 + 2 = 8
5 + 1 + 2 = 8
710:
7 + 1 + 0 = 8
7 + 1 + 0 = 8
The sum of the digits is 8, not 15. So, Option C is incorrect.
Option D: 432 – 513 – 711
432:
4 + 3 + 2 = 9
4 + 3 + 2 = 9
513:
5 + 1 + 3 = 9
5 + 1 + 3 = 9
711:
7 + 1 + 1 = 9
7 + 1 + 1 = 9
The sum of the digits is 9, not 15. So, Option D is incorrect.
Thus, correct option is (b).