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Select the set in which the numbers are related in the same way as are the numbers of the following sets. (NOTE : Operations should be performed on
Question

Select the set in which the numbers are related in the same way as are the numbers of the following sets.
(NOTE : Operations should be performed on the whole numbers, without breaking down the numbers into its constituent digits. E.g. 13 - Operations on 13 such as adding / subtracting/multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed)
(4,50,6),
(2,18,4)

A.

(15,162,3)

B.

(12,60,5)

C.

(5,62,6)

D.

(2,125,3)

Correct option is A

Given : 
( 4 , 50 ,6 ) , ( 2 , 18 , 4 )
Logics : 
[ { ( First number + Third number ) ÷\div 2 } ×\times ( First number + Third number ) ] = Second Number
( 4 , 50 , 6 )
[(4+6)2]×(4+6)][\frac{(4+6)}{2}]\times(4+6)] 
102×10\frac{10}{2}\times10 = 50
50 = 50 ( Follow)
( 2 , 18 , 4 )
=[(2+4)2]×(2+4)[\frac{(2+4)}{2}]\times(2+4)
18 = 18 ( Follow)
Option  (a) ( 15,  162 , 3 )
[(15+3)2]×(15+3)[\frac{(15+3)}{2}]\times(15+3)
9×18=1629\times18 = 162
162 = 162 (follow)
Option (b) ( 12 , 60 , 5 )
(12+5)2×(12+5)\frac{(12+5)}{2}\times (12+5)
8.5 ×\times 17 
144.5 \neq​ 60 ( does not follow)
Option (c) (5 , 62,  6 )
(5+6)2×(5+6)\frac{(5+6)}{2}\times(5+6)
5.5×115.5\times11 
60.5 \ne​ 62 ( does not follow )
Option (d) ( 2 , 125 , 3 )
(2+3)2×(2+3)\frac{(2+3)}{2}\times(2+3)
2.5 ×\times 5
12.5 \ne​  125  does not follow
Thus, the correct answer is (a) ( 15,  162 , 3 )
​​​

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