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    Select the set in which the numbers are related in the same way as are the numbers of the following sets. (NOTE : Operations should be performed on
    Question

    Select the set in which the numbers are related in the same way as are the numbers of the following sets.
    (NOTE : Operations should be performed on the whole numbers, without breaking down the numbers into its constituent digits. E.g. 13 - Operations on 13 such as adding / subtracting/multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed)
    (4,50,6),
    (2,18,4)

    A.

    (15,162,3)

    B.

    (12,60,5)

    C.

    (5,62,6)

    D.

    (2,125,3)

    Correct option is A

    Given : 
    ( 4 , 50 ,6 ) , ( 2 , 18 , 4 )
    Logics : 
    [ { ( First number + Third number ) ÷\div 2 } ×\times ( First number + Third number ) ] = Second Number
    ( 4 , 50 , 6 )
    [(4+6)2]×(4+6)][\frac{(4+6)}{2}]\times(4+6)] 
    102×10\frac{10}{2}\times10 = 50
    50 = 50 ( Follow)
    ( 2 , 18 , 4 )
    =[(2+4)2]×(2+4)[\frac{(2+4)}{2}]\times(2+4)
    18 = 18 ( Follow)
    Option  (a) ( 15,  162 , 3 )
    [(15+3)2]×(15+3)[\frac{(15+3)}{2}]\times(15+3)
    9×18=1629\times18 = 162
    162 = 162 (follow)
    Option (b) ( 12 , 60 , 5 )
    (12+5)2×(12+5)\frac{(12+5)}{2}\times (12+5)
    8.5 ×\times 17 
    144.5 \neq​ 60 ( does not follow)
    Option (c) (5 , 62,  6 )
    (5+6)2×(5+6)\frac{(5+6)}{2}\times(5+6)
    5.5×115.5\times11 
    60.5 \ne​ 62 ( does not follow )
    Option (d) ( 2 , 125 , 3 )
    (2+3)2×(2+3)\frac{(2+3)}{2}\times(2+3)
    2.5 ×\times 5
    12.5 \ne​  125  does not follow
    Thus, the correct answer is (a) ( 15,  162 , 3 )
    ​​​

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