Rutherford scattering proved the:
Rutherford scattering proved the presence of nucleus within an atom.
Explanation: Rutherford's experiment involved firing alpha particles at a thin gold foil and observing that most particles passed through, but a few were deflected at large angles. This led him to conclude that the atom must have a small, dense, positively charged core called the nucleus where most of the mass is concentrated.
a
An electron in a hydrogen atom (Bohr model) makes a transition from n = 2 state to n = 1 state. The frequency of the emitted photon is (take R = 1.0 × ):
Rutherford scattering proved the:
Suppose that an alpha particle of 4.50 MeV approaches head-on a uranium nucleus (Z = 92). Assuming that the uranium nucleus remains at rest and the alpha particle momentarily comes to rest and reverses its direction at a distance much more than the radius of the uranium nucleus, the distance of its closest approach is close to:
Consider the mass of iron nucleus as 55.85 u and A = 56. Then the nuclear density is:
Consider two nuclei, A of mass number 27 and B of mass number 64. Considering them as liquid-drops, the ratio of their densities will be:
The ratio of the longest wavelength to the shortest wavelength () in Brackett series of hydrogen spectrum is:
Rutherford scattering experiment is based on:
Suppose that an alpha particle of 3.20 MeV approaches head-on a lead nucleus (Z = 82). Assuming that the lead nucleus remains at rest and the alpha particle momentarily comes to rest and reverses its direction at a distance much more than the radius of the lead nucleus, the distance of its closest approach is:
The ratio of the longest wavelength to the shortest wavelength ( in Paschen series of hydrogen spectrum is:
Consider the solar system as a large atom. The quantum number (n) that characterises Earth's orbit (radius = 1.5 × m) with Earth moving at an orbital speed of 3 × m/s is (mass of Earth is 6 × kg):
