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    Rohan divides his complete journey in three equal parts and covers the first part at a speed of 30 km/h, the second part at 40 km/h and the last part
    Question

    Rohan divides his complete journey in three equal parts and covers the first part at a speed of 30 km/h, the second part at 40 km/h and the last part at 50 km/h with his car. What is the average speed (in km/h) of his car during his entire journey?

    A.

    38144738\frac{14}{47}​​

    B.

    35144735\frac{14}{47}​​

    C.

    40

    D.

    45

    Correct option is A

    Given:
    Rohan divides his journey into three equal parts.
    Speed during the first part(v1)(v_1)​ = 30 km/h
    Speed during the second part(v2)(v_2) ​= 40 km/h
    Speed during the third part(v3)(v_3)​ = 50 km/h

    Formula Used:

    Average speed=Total distanceTotal time\text{Average speed} = \frac{\text{Total distance}}{\text{Total time}}​​
    Solution:
    Let the total Distance be 3D. So, in each part it has to cover Distance = Dkm
    Time=D30+D40+D50=47D600\text{Time} = \frac{D}{30} + \frac{D}{40} + \frac{D}{50} = \frac{47D}{600}

    Average speed=Total distanceTotal time=3D47D600=180047=381447 km/h\text{Average speed} = \frac{\text{Total distance}}{\text{Total time}} = \frac{3D}{\frac{47D}{600}} = \frac{1800}{47} = 38 \frac{14}{47} \, \text{km/h}​​​



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