Correct option is A
Given: (Left) 7 $ 4 1 7 1 9 6 2 + 5 = 6 3 % 7 5 # 8 @ 4 5 & 7 8 (Right)
Logic: Odd Number | Symbol | Even Number

Three symbols are there each of which is immediately preceded by an oddnumber and also immediately followed by an even number.
Thus, correct option is (a).