Position of points O (0, 0) and P (2, -3) in the region of graph of inequality 2x - 3y < 5 will be:

Correct option is A

Correct Answer : (A) O inside and P outside.​

The inequality is: 2x−3y < 5

We need to check the position of the points O (0, 0) and P (2, -3) with respect to this inequality. 

1. For point O (0, 0), substitute $x=0$ and $y=0$ into the inequality: 2(0) − 3(0) = 0​

The inequality becomes: 0 < 5

This is true, so point O (0, 0) is inside the region.

2. For point P (2, -3) $x=2$ and  $y=-3$ into the inequality: 2(2) − 3(−3) = 4 + 9 = 13

The inequality becomes:  13 < 5

This is false, so point P(2, -3) is outside the region.

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