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    Pipes A and B can fill an empty cistern in 52 minutes and 65 minutes, respectively. Both Pipe A and Pipe B are opened together. After how much ti
    Question

    Pipes A and B can fill an empty cistern in 52 minutes and 65 minutes, respectively. Both Pipe A and Pipe B are opened together. After how much time should Pipe A be turned off so that the empty cistern is completely filled in a total of 60 minutes?

    A.

    20 min

    B.

    5 min

    C.

    15 min

    D.

    4 min

    Correct option is D

    Given:

    Pipe A fills the cistern in 52 minutes

    Pipe B fills the cistern in 65 minutes

    Both pipes are opened together

    The cistern is completely filled in 60 minutes

    Concept Used:
    If a pipe fills 1 tank in t minutes, its rate is 1t\frac{1}{t}​ per minute.
    Total work = 1 (full tank)

    Solution:

    Pipe A is turned off after x minutes

    Work by A in x minutes = x52\frac{x}{52}

    Work by B in 60 minutes = 6065\frac{60}{65}

    x52+6065=1\frac{x}{52} + \frac{60}{65} = 1​​

    x52=16065=565\frac{x}{52} = 1 - \frac{60}{65} = \frac{5}{65}​​

    x =565×52=26065=4 \frac{5}{65} \times 52 = \frac{260}{65} = 4 min

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