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    Pipe P is twice as fast as Q, and Q is twice as fast as R. Find the ratio of the time taken by P, Q and R to fill a cistern.
    Question

    Pipe P is twice as fast as Q, and Q is twice as fast as R. Find the ratio of the time taken by P, Q and R to fill a cistern.

    A.

    4 : 1 : 2

    B.

    4 : 2 : 1

    C.

    2 : 1 : 4

    D.

    1 : 2 : 4

    Correct option is D

    Given:
    Pipe P is twice as fast as pipe Q.
    Pipe Q is twice as fast as pipe R.
    Concept Used:
    If a pipe is faster, it takes less time to fill a cistern. Therefore, the time taken by each pipe is inversely proportional to its speed.
    Solution:
    Let the time taken by R to fill the cistern be T.
    Since Q is twice as fast as R, the time taken by Q is:
    T2.\frac{T}{2}.​​
    Since P is twice as fast as Q, the time taken by P is:
     = T2×12=T4.\frac{T}{2} \times \frac{1}{2} = \frac{T}{4}.​​
    Therefore, the time taken by P, Q, and R are T4,\frac{T}{4},​ T2,\frac{T}{2}​, and T respectively.
    Ratio of Time Taken by P, Q, and R:
    T4:T2:T\frac{T}{4} : \frac{T}{2} : T​ = 1 : 2 : 4.

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