Oxidation number of Mn in $$KMnO_4$$ is:​

Correct option is B

The correct answer is (B) +7

Explanation:
In the compound KMnO₄ (Potassium permanganate), the oxidation number of manganese (Mn) can be determined by considering the charges of the other elements in the compound.

• Potassium (K) always has an oxidation number of +1.

• Oxygen (O) in most compounds, including KMnO₄, typically has an oxidation number of -2.

Let the oxidation number of manganese (Mn) be x. The total oxidation number of the compound must equal zero since KMnO₄ is neutral.

The sum of oxidation numbers can be written as:

Oxidation number of K+Oxidation number of Mn+Oxidation number of 4 O=0\text{Oxidation number of K} + \text{Oxidation number of Mn} + \text{Oxidation number of 4 O} = 0

Substituting the known values:

​$$(+1)+x+4(−2)=0$$

$$1+x−8=0$$

$$x−7=0$$

$$x=+7$$​​​​​

Thus, the oxidation number of manganese in KMnO₄ is +7.

Information Booster:

• Oxidation number is a concept used to keep track of the electrons involved in redox reactions.

• In KMnO₄, manganese is in its highest oxidation state of +7.

• Potassium permanganate is commonly used as an oxidizing agent in redox reactions.

• The compound KMnO₄ is widely used in various chemical processes, including disinfection, bleaching, and as a titrant in redox titrations.

• Manganese compounds exhibit a variety of oxidation states, with +7 being the highest in KMnO₄.