Order the following electromagnetic radiation in terms of their decreasing energy:

[A] Infrared ray

[B] Gamma ray

[C] Visible ray

[D] Radio waves

Choose the correct answer from the options given below:

Correct option is B

Correct option: (b) — [B], [C], [A], [D]
Explanation of correct order (decreasing energy):
· Gamma rays (b):
· Highest frequency and shortest wavelength.
· Hence, maximum energy.
· Visible rays (c):
· Energy less than gamma rays but greater than infrared.
· Responsible for human vision.
· Infrared rays (a):
· Lower energy than visible light.
· Associated with heat radiation.
· Radio waves (d):
· Lowest frequency and longest wavelength.
· Hence, minimum energy.
➡️ Therefore, the decreasing energy order is: Gamma rays → Visible rays → Infrared rays → Radio waves
❌ Why other options are incorrect
Option (1): (a), (b), (c), (d)
· Infrared cannot have higher energy than gamma rays.
Option (3): (b), (a), (d), (c)
· Visible rays are incorrectly placed after radio waves.
Option (4): (c), (b), (d), (a)
· Gamma rays are not second to visible rays.
�� Key Points to Remember
· Energy of electromagnetic radiation ∝ frequency.
· Order of EM spectrum (high → low energy): Gamma > X-rays > UV > Visible > Infrared > Microwave > Radio
· Shorter wavelength = higher energy.