One number is 60% of another number. The larger number is 32 more than the smaller.
Find the larger number.

Correct option is C

​$$\textbf{Let the larger number be } x. \\\text{Then, the smaller number is } 60\% \text{ of } x = \frac{60}{100} \times x = 0.6x \\[10pt]\text{According to the question:} \\x = 0.6x + 32 \\[10pt]\text{Subtract } 0.6x \text{ from both sides:} \\x - 0.6x = 32 \Rightarrow 0.4x = 32 \\[10pt]\text{Now divide both sides by } 0.4: \\x = \frac{32}{0.4} = 80 \\[10pt]\boxed{\text{Larger number } = 80}$$​​