On a one-way road, to demarcate 4 lanes, line segments of 3.5 m length are painted with gaps of 3.5 m along the length of the road. What is the total length of the painted lines (in m) over a 350 m stretch of the road?

Correct option is C

Solution:

The length of the road = 350 m

Each cycle consists of a painted line of 3.5 m and a gap of 3.5 m.

Therefore, the length of one full cycle is 3.5 m + 3.5 m = 7 m

Therefore, number of cycles = 350 / 7 = 50 cycles

Since, each cycle has a painted line of 3.5 m, and there are three painted lines on the road to make 4 lane.

Total painted line length = 50 × 3.5 × 3 = 150 × 3.5 = 525

Thus, the total length of the painted lines over the 350 m stretch of road is 525 meters.

Hence Option (c) is correct.