4/7 of a pole is in the mud. When 1/3 of it is pulled out, an 8 meters long piece of the pole still remains in the mud. What is the total length of the pole?

Let the total length of the pole be L meters.

Initially, the part of the pole in the mud
= 4/7 × L
= 4L/7

When 1/3 of the part in the mud is pulled out,
the length pulled out from the mud
= (1/3) × (4L/7)
= 4L/21

So, the part of the pole still remaining in the mud
= 4L/7 − 4L/21

Taking LCM = 21,

= (12L − 4L) / 21
= 8L/21

According to the question, this remaining part is 8 meters.

So,
8L/21 = 8

Divide both sides by 8,

L/21 = 1

Therefore,
L = 21 meters