Correct option is A
Let the total length of the pole be L meters.
Initially, the part of the pole in the mud
= 4/7 × L
= 4L/7
= 4/7 × L
= 4L/7
When 1/3 of the part in the mud is pulled out,
the length pulled out from the mud
= (1/3) × (4L/7)
= 4L/21
the length pulled out from the mud
= (1/3) × (4L/7)
= 4L/21
So, the part of the pole still remaining in the mud
= 4L/7 − 4L/21
= 4L/7 − 4L/21
Taking LCM = 21,
= (12L − 4L) / 21
= 8L/21
= 8L/21
According to the question, this remaining part is 8 meters.
So,
8L/21 = 8
8L/21 = 8
Divide both sides by 8,
L/21 = 1
Therefore,
L = 21 meters
L = 21 meters
The total length of the pole is 21 meters.
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