Correct option is D
Given
z=200x+500y
Subject to
x+2y=10 ………………………….. (i)
3x+4y=24 ………………………….(ii)
From equation (i) & (ii), we get
(10, 0), (0, 5), (8, 0)& (0, 6)
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Objective function z=200x+500y, subject to the constrains x+2y≥10, 3x+4y≤24, x≥0, y≥0,
the minimum value of z is:
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