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​Match List I with List II​​Choose the correct answer from the options given below:​
Question

Match List I with List II

Choose the correct answer from the options given below:

A.

A-III, B-IV, C-I, D-II

B.

A-IV, B-III, C-II, D-I

C.

A-I, B-IV, C-II, D-III

D.

A-II, B-III, C-I, D-IV

Correct option is A

Solution:

Matching Standard Normal Intervals with ProbabilitiesA. 1Z+=>P(Z1)=1P(Z<1)=10.1587=0.84130.84=>IIIB. 1Z+1=>P(1Z1)=0.68260.82=>IVC. Z2=>P(Z2)=0.97720.98=>ID. 0Z2=>P(0Z2)=0.47720.48=>IIFinal Matching:A-III, B-IV, C-I, D-II\textbf{Matching Standard Normal Intervals with Probabilities}\\\begin{aligned}\text{A. } & -1 \leq Z \leq +\infty &&\Rightarrow P(Z \geq -1) = 1 - P(Z < -1) \\ & &&= 1 - 0.1587 = 0.8413 \approx \textbf{0.84} \Rightarrow \text{III} \\\\\text{B. } & -1 \leq Z \leq +1 &&\Rightarrow P(-1 \leq Z \leq 1) = 0.6826 \approx \textbf{0.82} \Rightarrow \text{IV} \\\\\text{C. } & -\infty \leq Z \leq 2 &&\Rightarrow P(Z \leq 2) = 0.9772 \approx \textbf{0.98} \Rightarrow \text{I} \\\\\text{D. } & 0 \leq Z \leq 2 &&\Rightarrow P(0 \leq Z \leq 2) = 0.4772 \approx \textbf{0.48} \Rightarrow \text{II}\end{aligned}\\[10pt]\textbf{Final Matching:} \quad \boxed{\text{A-III, B-IV, C-I, D-II}}

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