Correct option is A
Given:
Standard normal distribution properties:
- Area from −∞ to +∞ = 1
- Area from 0 to +1 ≈ 0.34
- Area from 0 to +2 ≈ 0.48
- Area from −∞ to +1 ≈ 0.84
- Area from −1 to +∞ ≈ 0.84
- Area from 0 to +2 ≈ 0.48
- Area from −2 to +2 ≈ 0.98
- Area from 0 to +2 ≈ 0.48
- Area from 0 to +2 plus 0.5 = 0.98
Concept:
Use standard normal table values:
- P(Z ≤ 1) ≈ 0.84
- P(Z ≥ −1) ≈ 0.84
- P(0 ≤ Z ≤ 2) ≈ 0.48
- P(−2 ≤ Z ≤ 2) ≈ 0.98
- P(0 ≤ Z ≤ 2) + 0.5 = 0.98
- P(0 ≤ Z ≤ 2) ≈ 0.48
- P(0 ≤ Z ≤ 2) ≈ 0.48
Solution:
A. −1 ≤ Z ≤ +∞
= P(Z ≥ −1)
≈ 0.84 → III
B. −∞ ≤ Z ≤ +1
= P(Z ≤ 1)
≈ 0.82→ IV
B → IV (≈ 0.82)
C. −∞ ≤ Z ≤ +2
= P(Z ≤ 2)
≈ 0.98 → I
D. 0 ≤ Z ≤ +2
≈ 0.48 → II
Final Matching:
A–III, B–IV, C–I, D–II
Final Answer:
Option A
