Let $$g:R\rightarrow R$$ and $$h:R\rightarrow R$$ be two given functions where $$R$$ is the set of real numbers and $$g(x)=x+3,h(x)=x^2+x-1,x\in R.$$ The g{h(–20)} is equal to​

Correct option is A

Solution:

$$g(x) = x + 3,\quad h(x) = x^2 + x - 1,\quad x \in \mathbb{R} \\[8pt]\text{We need to find: } g(h(-20)) \\[8pt]\text{Step 1: Evaluate } h(-20) \\h(-20) = (-20)^2 + (-20) - 1 = 400 - 20 - 1 = 379 \\[8pt]\text{Step 2: Apply } g(x) \text{ on the result} \\g(h(-20)) = g(379) = 379 + 3 = 382 \\[12pt]\boxed{\text{Final Answer: } 382}$$

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