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    ​Let {En} be a sequence of subsets of R.Define lim sup⁡nEn=⋂k=1∞⋃n=k∞Enlim inf⁡nEn=⋃k=1∞⋂n=k∞EnWhich&nbsp
    Question

    Let {En} be a sequence of subsets of R.Define lim supnEn=k=1n=kEnlim infnEn=k=1n=kEnWhich of the following statements is true?\text{Let } \{E_n\} \text{ be a sequence of subsets of } \mathbb{R}. \\\text{Define }\\\limsup_{n} E_n = \bigcap_{k=1}^\infty \bigcup_{n=k}^\infty E_n\\\liminf_{n} E_n = \bigcup_{k=1}^\infty \bigcap_{n=k}^\infty E_n\\\text{Which of the following statements is true?}​​

    A.

    ​​lim supnEn=lim infnEn\limsup_n E_n = \liminf_n E_n​​

    B.

    lim supnEn={x:xEn for some n}\limsup_n E_n = \{x : x \in E_n \text{ for some } n\}​​

    C.

    lim infnEn={x:xEn for all but finitely many n}\liminf_n E_n = \{x : x \in E_n \text{ for all but finitely many } n\}​​

    D.

    lim infnEn={x:xEn for infinitely many n}\liminf_n E_n = \{x : x \in E_n \text{ for infinitely many } n\}​​

    Correct option is C

    n=1En=E1E2n=2En=E2E3n=3En=E3E4 k=1n=kEn=lim infnEnSo, lim infnEn contains those x such that xEn for all but finitely many n.\bigcap_{n=1}^\infty E_n = E_1 \cap E_2 \cap \dots \cap \dots\\\bigcap_{n=2}^\infty E_n = E_2 \cap E_3 \cap \dots \cap \dots\\\bigcap_{n=3}^\infty E_n = E_3 \cap E_4 \cap \dots \cap \dots\\\implies \bigcup_{k=1}^\infty \bigcap_{n=k}^\infty E_n = \liminf_n E_n\\\text{So, } \liminf_n E_n \text{ contains those } x \text{ such that } \\x \in E_n \text{ for all but finitely many } n.​​

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