Given:
O is the incentre of the triangle.
∠ABC = 70° and ∠ACB = 50°
Formula Used:
Angle of the incentre of the triangle is equal to the sum of 90° and half of the angle opposite to the incentre of a triangle.
Sum of all angles of triangle =180°
Solution:
70° + 50° +∠BAC = 180
∠BAC = 60°
∠BOC = 90° +
=90°+30°
=120°
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60 Mins English English25 Questions50 Marks15 Mins English English100 Questions200 Marks60 Mins EnglishIn triangle ABC, medians AD, BE, and CF intersect at the centroid G. What is the ratio of the area of triangle GAB to the area of triangle ABC?
The circumradius of a triangle is 9 cm while the inradius of it is 4 cm. What is the distance between the circumcentre and the incentre of the triangle?
Read the given statements carefully and decide which option is correct with respect to the statements.
Statements:
1. In any triangle, the concurrent point of medians is a centroid.
2. In any triangle, the concurrent point of altitudes is an orthocentre.
3. In any triangle, the concurrent point of internal angular bisectors is an in-centre.
ABC is a right-angled triangle. If the lengths of two sides containing the right angle are 4 cm and 3 cm, the radius of its incircle is:
If the inradius of a triangle with perimeter 64 cm is 8 cm, then find the area of the triangle.
The mid points of AB and AC of a △ABC are X and Y, respectively. If BC+XY=18 units, then the value of BC-XY is:
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