Let 30 cm and 18 cm be the lengths of the two parallel sides of a trapezium and 24 cm be distance between these two sides. If the area of this trapezium is equal to the area of a square, then the perimeter of the square will be:

Correct option is C

Given:
30 cm and 18 cm be the lengths of the two parallel sides of a trapezium
24 cm be distance between these two sides
Formula Used:
 Area of Trapezium $$= \frac{1}{2} ×(a+b)×h$$  

Area of square = $$a^2$$  ( where a is the side of square)

Perimeter of square = 4a

​Solution:
a=30cm
b=18 cm
h=24 cm
​$$Area=\frac{1}{2}×(30+18)×24 \\\ \\= \frac{1}{2} ×48×24 \\\ \\=24×24 \\\ \\=576cm^2$$​​
So, the area of the trapezium is 576 cm².
The area of trapezium is equal to the area of a square, we can set up the equation:
Area of Square= 576 cm$$^2$$ 

Let the side of the square = a 

According to the question,

$$a^2$$​=576 
a=√576= 24cm
The perimeter of a square with side length s is given by:
Perimeter=4×a
Perimeter =4×24
= 96 cm