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John and Jenny stood at a point facing the north. John left Jenny in the morning and walked towards the west for 3 km, taking 15 minutes. Then he move
Question

John and Jenny stood at a point facing the north. John left Jenny in the morning and walked towards the west for 3 km, taking 15 minutes. Then he moved towards the south for 4 km, taking 25 minutes. What is the shortest distance Jenny needs to travel to meet John?

A.

8 km

B.

4 km

C.

5 km

D.

7 km

Correct option is C

Given:
John and Jenny stood at a point facing north.
John left Jenny in the morning.
He walked 3 km west in 15 minutes.
Then he moved 4 km south in 25 minutes.
Logic:(Hypotenuse)2=(Base)2+(Perpendicular)2(\text{Hypotenuse})^2 = (\text{Base})^2 + (\text{Perpendicular})^2
According to the given information, Path diagram will be:
Using the Pythagoras's theorem:
d=(32)+(42)d = \sqrt{(3^2) + (4^2)}
d=9+16d = \sqrt{9 + 16}
d=25=5 kmd = \sqrt{25} = 5 \text{ km}
Therefore, shortest distance Jenny needs to travel to meet John is 5 Km towards South-West direction.
Thus, the correct option is (c) 5 Km

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