In the number ‘924831675’, how many pairs of the digits have the same number between them (both forward and backward direction) as in the number series?

Correct option is B

Check valid pairs:
2 and 4
Between in number = 1 (digit 4 is at pos3, so actually between = 0 ) → Not valid

2 and 3
Positions: 2 & 5 → between in number = 2 (4, 8)
Number series: 2 → 3 → between = 0 → Not valid

4 and 6
Positions: 3 & 7 → between = 3 (8, 3, 1)
Number series: 4 → 6 → between = 1 → Not valid

3 and 6
Positions: 5 & 7 → between = 1 (1)
Number series: 3 → 6 → between = 2 → Not valid

6 and 7
Positions: 7 & 8 → between = 0
Number series: 6 → 7 → between = 0  → Valid pair

7 and 5
Positions: 8 & 9 → between = 0
Number series: 7 → 5 → between = 1 → Not valid

1 and 3
Positions: 6 & 5 → between = 0
Number series: 1 → 3 → between = 1 → Not valid

1 and 4 (in backward)
Positions: 4 & 7 → between = 3, 8
Number series: 1 → 4 → between = 2 →  valid

Final Answer:
2 pairs satisfy the condition