In how many possible ways can 1500 be divided into two factorizations?
Given:
Number = 1500
Formula Used:
If the prime factorization of N is the total number of factors is (a+1) × (b+1)
Number of ways to express as a product of two factors is
Solution:
Prime factorization of 1500 is
Total factors = (2+1) × (1+1) × (3+1)
Total factors = 3 × 2 × 4 = 24
Number of ways = = 12
Final Answer
So the correct answer is (a)
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Suggested Test Series
Suggested Test Series
The product of two consecutive positive multiples of 5 is 750. What is the smaller of the two numbers?
The product of two consecutive even numbers is 624. What is the sum of the two numbers?
The sum of the squares of two positive integers is 1025 and difference of their squares is 225 . The difference of the numbers is what percent of the product of these numbers ?
If then how many positive factors does N have ?
When is written in decimal notation, then the sum of digits will be
The sum of five consecutive multiples of 8 is 560. The smallest multiple is
A two-digit number is 4 times the sum of its digits and twice the product of the digits. The number is:
The product of the predecessor of 201 and the successor of 4781 is:
The number of positive prime integer <50 is
