In a round-robin tournament (each team plays with all other teams once) between 8 teams, a win fetched 3 points and a draw. 1. After each team had played 4 matches, the total of the points of the teams was 34. The number of drawn games among those played till then was

Correct option is D

Given : 
Total teams = 8
Points earn for win = 3
Points earn for draw = 1
total points scored by all teams is =  34
Solution : 
Each team plays 4 matches, and there are 8 teams. However, each match involves 2 teams, so the total number of matches played so far is: $$\frac{8 * 4}{2}$$ = 16
For a win: 3 points are awarded to the winning team, and the losing team gets 0 points.
For a draw: 1 point is awarded to each team, resulting in 2 points in total for that match.
Let the number of drawn games be
Each drawn match contributes 2 points (1 point per team), so the total points from  draws is 2
The remaining 16− matches are wins, and each win contributes 3 points.
Therefore, the total points from wins is 3(16−)
Adding these together: 2x+3(16−x)=34
Solve for
2x+48−3x=34=>−x+48=34=>x=48−34=14.
​ The number of drawn games is  14
Thus the correct answer is option (d) 14