In a race, an athlete covers a distance of 312 m in 104 sec in the first lap. He covers the second lap of the same length in 52 sec. What is the average speed (in m/sec) of the athlete?

Correct option is D

​Given:

Distance of each lap = 312 m

Time for first lap = 104 sec

Time for second lap = 52 sec

Formula Used:

Average speed = $$\frac{\text{Total distance}}{\text{Total time}}$$​​

Solution:​

Total distance = 312 + 312 = 624 m

Total time = 104 + 52 = 156 sec

Average speed = $$\frac{624}{156} = 4 \text{ m/sec}$$​​