In a group of cows and hens, the number of legs are 14 more than twice the number of heads. The number of cows is :

Correct option is B

Let:
- x = Number of cows
- y = Number of hens

Each cow has **1 head and 4 legs**, and each hen has **1 head and 2 legs**.

Given:
1. Total heads = x + y (since each animal has 1 head).
2. Total legs = 4x + 2y (cows have 4 legs, hens have 2 legs).
3. The number of legs is **14 more than twice the number of heads**:
4x + 2y = 2(x + y) + 14

Solution:
Simplify step-by-step:
1. Start with the given equation:
4x + 2y = 2(x + y) + 14

2. Expand 2(x + y) :
4x + 2y = 2x + 2y + 14

3. Subtract 2x + 2y from both sides:
4x - 2x + 2y - 2y = 14

Simplify:
2x = 14
4. Solve for x :
x = $$\frac{14}{2} = 7$$​
Final Answer:
The number of cows is 7.

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