In a family, there are six members named K, L, M, N, O and P. N's age is three times the age of L. The age of O is equal to the total age of L and M. P's age is equal to the total age of K and N. K's age is half the age of M. P is one year elder than O. The sum of the ages of K and M is 45 years. The sum of ages of N and L is 32 years.

Which of the following is true based on the given information?

I. The age of P is 41 years.

II. O is 21 years elder than K.​​​​​

Given: 

1. N's age is 3 times L's

2. O's age = L + M

3. P = K + N

4. K = half of M

5. P is 1 year older than O

6. K + M = 45

7. N + L = 32

​K = $$\frac {1}{2}$$​M

So, K + M = 45
​$$\frac {1}{2}$$​M + M = 45
1.5 M = 45
M = 30
K = $$\frac {1}{2}$$​ × 30 = 15

N = 3 × L

So, N + L = 32
3L + L = 32
4L = 32
L = 8
N = 3 × 8 = 24

O = L + M = 8 + 30 = 38

P = K + N = 15 + 24 = 39

P = O + 1 = 38 + 1 = 39

K = 15, L = 8, M = 30, N = 24, O = 38, P = 39

I. The age of P is 41 years. (False)

II. O is 21 years elder than K. (False)

Thus, correct option is (c).